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45x^2-170x-40=0
a = 45; b = -170; c = -40;
Δ = b2-4ac
Δ = -1702-4·45·(-40)
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36100}=190$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-170)-190}{2*45}=\frac{-20}{90} =-2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-170)+190}{2*45}=\frac{360}{90} =4 $
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